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Chapter 9: Problem 9
Use the quadratic formula to solve each equation. (All solutions for theseequations are real numbers.) $$ 2 x^{2}-2 x=1 $$
Short Answer
Expert verified
The solutions are \( x = \frac{1 + \sqrt{3}}{2} \) and \( x = \frac{1 - \sqrt{3}}{2} \).
Step by step solution
01
Arrange the equation in standard form
To use the quadratic formula, the equation must be in the form \( ax^2 + bx + c = 0 \). Starting with the equation \[ 2x^2 - 2x = 1 \], subtract 1 from both sides to get: \[ 2x^2 - 2x - 1 = 0 \].
02
Identify coefficients
For the quadratic equation \( 2x^2 - 2x - 1 = 0 \), identify the coefficients: \( a = 2 \), \( b = -2 \), and \( c = -1 \).
03
Write down the quadratic formula
The quadratic formula is \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \].
04
Substitute the coefficients into the formula
Insert the values of \( a \), \( b \), and \( c \) into the quadratic formula: \[ x = \frac{-(-2) \pm \sqrt{(-2)^2 - 4 \cdot 2 \cdot (-1)}}{2 \cdot 2} \].
05
Simplify under the square root
Simplify the expression under the square root: \[ (-2)^2 - 4 \cdot 2 \cdot (-1) = 4 + 8 = 12 \]. So the formula now is: \[ x = \frac{2 \pm \sqrt{12}}{4} \].
06
Simplify the square root
Simplify \( \sqrt{12} \) to get \( 2\sqrt{3} \). The equation now is: \[ x = \frac{2 \pm 2\sqrt{3}}{4} \].
07
Simplify the fraction
Factor out the 2 from the numerator and simplify: \[ x = \frac{2(1 \pm \sqrt{3})}{4} = \frac{1 \pm \sqrt{3}}{2} \].
08
State the solutions
The solutions to the equation are: \[ x = \frac{1 + \sqrt{3}}{2} \] and \[ x = \frac{1 - \sqrt{3}}{2} \].
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
solving quadratic equations
Quadratic equations are mathematical expressions of the form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants and \( x \) represents the variable. To solve these equations, one effective method is the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]?. This formula helps find the values of \( x \) that satisfy the equation.
First, ensure the equation is in its standard form. For example, given \( 2x^2 - 2x = 1 \), transform it into \( 2x^2 - 2x - 1 = 0 \). Next, identify the coefficients, plug them into the formula, and simplify each step.
identifying coefficients
Identifying the coefficients \( a \), \( b \), and \( c \) is essential in solving a quadratic equation using the quadratic formula.
For instance, in the equation \( 2x^2 - 2x - 1 = 0\):
- \( a \) is the coefficient of \( x^2 \), so \( a = 2 \).
- \( b \) is the coefficient of \( x \), so \( b = -2 \).
- \( c \) is the constant term, so \( c = -1 \).
After identifying these coefficients, you can substitute them in the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) to find the solution.
simplifying expressions
Simplifying expressions is an important step in solving the quadratic equation. Once you have substituted the coefficients into the quadratic formula, you need to simplify each part step by step.
Start by working under the square root (the discriminant):\[ b^2 - 4ac \]. For our example with \( b = -2 \), \( a = 2 \), and \( c = -1 \), it becomes: \( (-2)^2 - 4 \cdot 2 \cdot (-1) = 4 + 8 = 12 \).
Next, simplify the square root: \( \sqrt{12} \) simplifies to \( 2\sqrt{3} \). Finally, simplify the fraction step by step to get the final solution:
- Simplify the numerator: \( 2 \pm 2\sqrt{3} \)
- Factor out common terms if possible and simplify the fraction: \( \frac{2(1 \pm \sqrt{3})}{4} = \frac{1 \pm \sqrt{3}}{2} \)
square roots
Square roots are crucial in the quadratic formula as they often determine the solutions' complexity. In the quadratic formula, you will encounter the term \( \sqrt{b^2 - 4ac} \), where \( b^2 - 4ac \) is the discriminant.
Simplifying square roots is essential. For instance, \( \sqrt{12} \) simplifies to \( 2\sqrt{3} \). This is because 12 can be factored into \( 4 \times 3 \), and since \( \sqrt{4} \) is 2, it evolves into \( 2\sqrt{3} \).
Simplifying square roots helps simplify the quadratic formula and obtain a clean final solution. The expressions become easier to handle, making it simpler to interpret the final solutions: \[ x = \frac{1 + \sqrt{3}}{2} \] and \[ x = \frac{1 - \sqrt{3}}{2} \].
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